Question
The value of $\frac{4\sqrt{12}}{12\sqrt{27}}$ is:
- $\frac{1}{9}$
- $\frac{2}{9}$
- $\frac{4}{9}$
- $\frac{8}{9}$
Solution:
$\frac{4\sqrt{12}}{12\sqrt{27}}=\frac{4\sqrt{4\times3}}{12\sqrt{9\times3}}$
$=\frac{2\sqrt{3}}{3\times3\sqrt{3}}=\frac{2}{9}$
Hence, the correct answer is option (b).
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