MCQ
The value of $\frac{\cot x-\tan x}{\cot 2 x}$ is
  • A
    1
  • 2
  • C
    -1
  • D
    4

Answer

Correct option: B.
2
(B)
$\frac{\cot x-\tan x}{\cot 2 x}=\frac{\cos ^2 x-\sin ^2 x}{\sin x \cos x} \times \frac{\sin 2 x}{\cos 2 x}$
$-\frac{2 \cos 2 x}{\sin 2 x} \times \frac{\sin 2 x}{\cos 2 x}-2$

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