MCQ
The value of $\frac{T_3}{T_1}$ is .............


- A$1$
- B$2$
- ✓$3$
- D$\frac{3}{2}$

$a =0$
$T _1=5\,g$
$T _2- T _1=5\,g$
$T _3- T _2=5\,g$
solving the above $3$ eq. you get
$T _1=50$
$T _2=100$
$T _3=150$
$so \frac{ T _3}{ T _1}=3$
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