The value of equivalent capacitance of the combination shown in figure between the points $P$ and $Q$ is
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the left $C$ and $C$, capacitors are in parallel to the add up to equivalent of $2 C$

now, this $2 \mathrm{C}$ is in series with the left middle $2 \mathrm{C}$ so, it will add up to Ceq of $\mathrm{C} \ldots$

again this $\mathrm{C}$ is parallel with middle centre $\mathrm{C},$ adding up to $2 \mathrm{C}$

now again, this $2 \mathrm{C}$ is in series with the left upper $2 \mathrm{C}$ so, it will add up to Ceq of $\mathrm{C} \ldots$

and finally this $C$ is in parallel with $2 C$

so, the final $\operatorname{ceq}$ is $C+2 C=3 C$

art

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