MCQ
The value of Henry’s constant $K_H$ is $.......$
- AGreater for gases with higher solubility.
- ✓Greater for gases with lower solubility.
- CConstant for all gases.
- DNot related to the solubility of gases.
✓
Answer
Correct option: B.
Greater for gases with lower solubility.
The value of Henry's constant $K_H$ is greater for gases with lower solubility because of the mathematical relation.
$\text{P}=\text{K}_\text{H}\times\text{x}$
$\text{K}_\text{H}=\frac{\text{P}}{\text{x}}$
where$, K_H$ represents Henry's constant$, p$ is partial pressure of the gas in vapour phase, and $x$ denotes mole fraction of the gas in solution. Thus $K_H$ is inversely proportional to mole fraction of gas in solution $($representing its solubility$).$
$\text{P}=\text{K}_\text{H}\times\text{x}$
$\text{K}_\text{H}=\frac{\text{P}}{\text{x}}$
where$, K_H$ represents Henry's constant$, p$ is partial pressure of the gas in vapour phase, and $x$ denotes mole fraction of the gas in solution. Thus $K_H$ is inversely proportional to mole fraction of gas in solution $($representing its solubility$).$
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