MCQ
The value of $I_c$ for the configuration shown is....$ mA$
  • $3.53$
  • B
    $4.68$
  • C
    $2.95$
  • D
    $5.72$

Answer

Correct option: A.
$3.53$
a
$I_{B}=\cdot \frac{V_{C C}-V_{B E}}{R_{B}}=\frac{12 \mathrm{V}-0.7 \mathrm{V}}{240 \mathrm{k} \Omega}=47.08 \mu \mathrm{A}$

$I_{C}=\beta I_{B}$

$=(75)(47.08 \mu A)=3.53 \mathrm{\,mA}$

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