MCQ
The value of $\int_{\,0}^{\,\sqrt 2 } {[{x^2}]\,dx} ,$ where $[.]$ is the greatest integer function
  • A
    $2 - \sqrt 2 $
  • B
    $2 + \sqrt 2 $
  • $\sqrt 2 - 1$
  • D
    $\sqrt 2 - 2$

Answer

Correct option: C.
$\sqrt 2 - 1$
c
(c) $I = \int_0^{\sqrt 2 } {[{x^2}]\,\,dx} $

$ = \int_{\,0}^{\,1} {[{x^2}]\,dx + } \int_{\,1}^{\,\sqrt 2 } {[{x^2}]\,\,dx} $

$ = \int_{\,0}^{\,1} {\,0\,dx + } \int_{\,1}^{\,\sqrt 2 } {\,dx} $

$ = [x]_1^{\sqrt 2 } = \sqrt 2 - 1$.

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