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STD 12 - 7.2 definite integral — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 7.2 definite integral4 Marks
Question
The value of $\int\limits_{ - 1}^1 {\frac{{dx}}{{\sqrt {\,|\,x\,|} }}} \,\,$ is
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Answer

c
$2\,\int\limits_0^1 {\frac{{dx}}{{\sqrt x }}} $ $=\left[ {\frac{{{x^{ - \frac{1}{2} + 1}}}}{{ - \frac{1}{2} + 1}}} \right]_{\,0}^{\,1}$ $= 4\, \left[ {\sqrt x } \right]_{\,0}^{\,1}$ $= 4$ 

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