MCQ
The value of $\int\limits_{ - 1}^1 {\frac{{dx}}{{\sqrt {\,|\,x\,|} }}} \,\,$ is
  • A
    $\,\frac{1}{2}\,$
  • B
    $2$
  • $4$
  • D
    undefined

Answer

Correct option: C.
$4$
c
$2\,\int\limits_0^1 {\frac{{dx}}{{\sqrt x }}} $ $=\left[ {\frac{{{x^{ - \frac{1}{2} + 1}}}}{{ - \frac{1}{2} + 1}}} \right]_{\,0}^{\,1}$ $= 4\, \left[ {\sqrt x } \right]_{\,0}^{\,1}$ $= 4$ 

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Find the value of $x,\,y$ and $z$ from the following equation : $\left[\begin{array}{ll}x+y & 2 \\ 5+z & x y\end{array}\right]=\left[\begin{array}{ll}6 & 2 \\ 5 & 8\end{array}\right]$
If $f(x) = \left\{ \begin{array}{l}\,\,\,\,\,\,\,\,\,\frac{{1 - \cos 4x}}{{{x^2}}},\;\;{\rm{when}}\,x < 0\\\,\,\,\,\,\,\,\,\,\,\,a,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{when}}\,\,x = 0\\\frac{{\sqrt x }}{{\sqrt {(16 + \sqrt x )} - 4}},\,\,{\rm{when}}\,\, x > 0\end{array} \right.$, is continuous at $x = 0$, then the value of $'a'$ will be
If $\text{P}(\text{A}\cup\text{B})=0.8$ and $\text{P}(\text{A}\cap\text{B})=0.3$ then $\text{P}(\overline{\text{A}})=\text{P}(\overline{\text{B}})=$
If $\tan^{-1}\frac{\text{x}+1}{\text{x}-1}+\tan^{-1}\frac{\text{x}-1}{\text{x}}=\tan^{-1}(-7),$ then the value of $x$ is:
If the system of equations

$ x+(\sqrt{2} \sin \alpha) y+(\sqrt{2} \cos \alpha) z=0 $

$ x+(\cos \alpha) y+(\sin \alpha) z=0 $

$ x+(\sin \alpha) y-(\cos \alpha) z=0$

has a non-trivial solution, then $\alpha \in\left(0, \frac{\pi}{2}\right)$ is equal to :

The maximum value of $\triangle=\begin{vmatrix}1&1&1\\1&1+\sin\theta&1\\1+\cos\theta&1&1\end{vmatrix}$ is $(\theta$ is real$):$
If  $f(x) = \left\{ \begin{array}{l}\frac{5}{2} - x\,,\,{\rm{when\,\,}}\,x < 2\\\,\,\,1\,\,\,\,\,\,,\,{\rm{when \,\,}}x = 2\\x - \frac{3}{2},{\rm{when\,\,}}\,x > 2\end{array} \right.$, then
A straight line L on the xy-plane bisects the angle between OX and OY. What are the direction cosines of L:
If $\frac{\pi }{2} \le x \le \frac{{3\pi }}{2},$ then ${\sin ^{ - 1}}(\sin x)$ is equal to
$\int_0^{\pi /2} {} (\sin x - \cos x)\log (\sin x + \cos x)\,dx = $