MCQ
The value of $\int\limits_0^2 {\frac{{dx}}{{{{(1 - x)}^2}}}} $ is
  • A
    $-2$
  • B
    $0$
  • C
    $15$
  • indeterminate

Answer

Correct option: D.
indeterminate
d
$\int\limits_0^2 {\frac{{dx}}{{{{(1 - x)}^2}}}} $ $= \int\limits_0^{{1^ - }} {\frac{{dx}}{{{{(1 - x)}^2}}}} \,\, + \,\,\int\limits_{{1^ + }}^2 {\frac{{dx}}{{{{(1 - x)}^2}}}} \,$

$= \left. {\frac{1}{{1 - x}}} \right]_0^{{1^ - }}\,\, + \,\,\left. {\frac{1}{{1 - x}}} \right]_{{1^ + }}^2$

$= (\infty - 1) + (-1) - (- \infty ) \Rightarrow$ indeterminant

Note that the shaded area is divergent 

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