MCQ
The value of $k$ which makes $f(x) = \left\{ \begin{array}{l}\sin \frac{1}{x},\;x \ne 0\\\,\,\,\,\,\,\,\,k,\,x = 0\end{array} \right.$ continuous at $x = 0$ is
- A$8$
- B$1$
- C$-1$
- ✓None of these
therefore limit of the function does not exist at $x = 0.$
Hence there is no value of $k$ for which the function is continuous at $x = 0.$
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