MCQ
The value of $\left[\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}\right] \div\left(\frac{1}{5}\right)^{-2}$ is
  • A
    $0$
  • B
    $-1$
  • $1$
  • D
    $\frac{7}{5}$

Answer

Correct option: C.
$1$
${\left[\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}\right] \div\left(\frac{1}{5}\right)^{-2}}$
$=\left(3^2+4^2 \div 5^2\right.$
$=(9+16) \div 25$
$=25 \div 25$
$=1$

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