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Limits — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsLimits2 Marks
MCQ
The value of $\lim _{n \rightarrow \infty} \frac{1-n^2}{\sum n}$ will be
  • ✓
    -2
  • B
    -1
  • C
    2
  • D
    1
✓

Answer

Correct option: A.
-2
(A)
$\lim _{n \rightarrow \infty} \frac{1-n^2}{\sum n}=\lim _{n \rightarrow \infty} \frac{(1-n)(1+n)}{\frac{n(n+1)}{2}}=\lim _{n \rightarrow \infty} \frac{2(1-n)}{n}$
$=2 \lim _{n \rightarrow \infty}\left(\frac{1}{n}-1\right)=2(-1)=-2$

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