MCQ
The value of $ \lim\limits_{\text{x} \rightarrow 3^{+}} \dfrac{|\text{x}-3|}{\text{x}-3}$ equals:
- A1
- B-1
- C0
- DDoes not exist
Solution:
for $ \text{x}=30^+,$
$ \text{ x}-3 > 0$
Let $\text{L}=\displaystyle \lim_{\text{x}-3^+}\dfrac {|\text{x}-3|}{\text{x}-3}$
$ =\displaystyle \lim_{\text{x}\rightarrow 3^+}$
$ =\dfrac{(\text{x}-3)}{(\text{x}-3)}$
$ = \lim\limits_{\text{x}\rightarrow 3^+}(1) =1$
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