MCQ
The value of $\mathop {\lim }\limits_{n \to \infty } \frac{{1 + 2 + 3 + ....n}}{{{n^2} + 100}}$ is equal
- A$\infty $
- ✓$\frac{1}{2}$
- C$2$
- D$0$
$ = \mathop {\lim }\limits_{n \to \infty } \frac{{n(n + 1)}}{{2({n^2} + 100)}} = \mathop {\lim }\limits_{n \to \infty } \frac{{{n^2}\left( {1 + \frac{1}{n}} \right)}}{{2{n^2}\left( {1 + \frac{{100}}{{{n^2}}}} \right)}} = \frac{1}{2}$.
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$M =\left\{( x , y ) \in R \times R : x ^2+ y ^2 \leq r ^2\right\},$
where $r >0$. Consider the geometric progression $a _{ n }=\frac{1}{2^{ n -1}}, n =1,2,3, \ldots$. Let $S _0=0$ and, for $n \geq 1$, let $S _{ n }$ denote the sum of the first $n$ terms of this progression. For $n \geq 1$, let $C_n$ denote the circle with center $\left(S_{n-1}, 0\right)$ and radius $a _{ n }$, and $D _{ n }$ denote the circle with center $\left( S _{ n -1}, S _{ n -1}\right)$ and radius $a _{ n }$.
($1$) Consider M with $r =\frac{1025}{513}$. Let $k$ be the number of all those circles $C _{ n }$ that are inside $M$. Let $l$ be the maximum possible number of circles among these $k$ circles such that no two circles intersect. Then
$(A)$ $k +2 l=22$ $(B)$ $2 k +l=26$ $(C)$ $2 k +3 l=34$ $(D)$ $3 k +2 l=40$
($2$) Consider $M$ with $r =\frac{\left(2^{199}-1\right) \sqrt{2}}{2^{158}}$. The number of all those circles $D _{ a }$ that are inside $M$ is
$(A) 198$ $(B) 199$ $(C) 200$ $(D) 201$
Give the answer or qution ($1$) and ($2$)