MCQ
The value of $\mathop {\lim }\limits_{x \to \infty } \frac{{\log x}}{{{x^n}}},\;n > 0$ is
  • $0$
  • B
    $1$
  • C
    $\frac{1}{n}$
  • D
    $\frac{1}{{n!}}$

Answer

Correct option: A.
$0$
a
(a) ${\rm{ }}\mathop {\lim }\limits_{x \to \infty } \,\frac{{\log x}}{{{x^n}}} = \mathop {\lim }\limits_{x \to \infty } \,\frac{1}{{n{x^n}}} = 0$ (By  $L-$ Hospital's rule)

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