Question
The value of $\sin \left(2 \tan ^{-1}(0.75)\right)$ is equal to

Answer

$\text { (c) : Let } 2 \tan ^{-1}(0.75)=\theta$
$\Rightarrow 0.75=\tan \left(\frac{\theta}{2}\right)$
$\therefore \sin \left(2 \tan ^{-1}(0.75)\right)$
$=\sin \theta=\frac{2 \tan \theta / 2}{1+\tan ^2 \theta / 2}=\frac{2 \times 0.75}{1+(0.75)^2}=\frac{1.50}{1.5625}=0.96$

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