MCQ
The value of $\sin^229^\circ+\sin^261^\circ$ is:
- ✓$1$
- B$0$
- C$2\sin^2{29}^\circ$
- D$2\cos^2{61}^\circ$
✓
Answer
Correct option: A.
$1$
$\sin^2{29}^\circ+\sin^2{61}^\circ$
$=\sin^2{29}^\circ+\sin^2{(90^\circ-29^\circ})$
$=\sin^2{29}+\cos^2{29}^\circ$
$(\sin^2\theta+\cos^2\theta=1)$
$=\sin^2{29}^\circ+\sin^2{(90^\circ-29^\circ})$
$=\sin^2{29}+\cos^2{29}^\circ$
$(\sin^2\theta+\cos^2\theta=1)$
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