MCQ
The value of $\sqrt{3-2\sqrt{2}}$ is:
- A$\sqrt{3}+\sqrt{2}$
- B$\sqrt{3}-\sqrt{2}$
- C$\sqrt{2}+1$
- D$\sqrt{2}-1$
✓
Answer
- $\sqrt{2}-1$
Solution:
$\sqrt{3-2\sqrt{2}}=\sqrt{\big(\sqrt{2}\big)^2+(1)^2-2\times\sqrt{2}\times1}$
$=\sqrt{\big(\sqrt{2}-1\big)^2}$
$=\sqrt{2}-1$
Hence, the correct option is (d).
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