Question
The value of $\sqrt[4]{(64)^{-2}}$ is:
- $\frac{1}{8}$
- $\frac{1}{2}$
- $8$
- $\frac{1}{64}$
✓
Answer
- $\frac{1}{8}$
Solution:
$\sqrt[4]{(64)^{-2}}=\sqrt[4]{(8^2)^{-2}}=8^{-4\times\frac{1}{4}}=8^{-1}=\frac{1}{8}$
Hence, the correct answer is option (a).
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