MCQ
The value of $\sqrt[4]{\sqrt[3]{2^2}}$ is:
  • A
    $2^{\frac{1}{6}}$
  • B
    $2^6$
  • C
    $2^{-6}$
  • D
    $2^{\frac{-1}{6}}$

Answer

  1. $2^{\frac{1}{6}}$
    Solution:
    $\sqrt[4]{\sqrt[3]{2^2}}$
    $=\sqrt[4]{\sqrt{2^{\frac{2}{3}}}}$
    $=2^{\frac{2}{3\times4}}=2^{\frac{1}{6}}$

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