Question
The value of $(\tan1^\circ\tan^\circ...\tan89^\circ)$ is equal to _________.

Answer

The value of $(\tan1^\circ\tan^\circ...\tan89^\circ)$ is equal to 1
$=\tan 1^\circ\tan2^\circ\tan3^\circ...\tan89^\circ$
$=\tan (90^\circ-89^\circ)\tan (90^\circ-88^\circ) \\ \tan (90^\circ-87^\circ)...\tan 87^\circ \tan 88^\circ\tan 89^\circ$
$=\cot 89^\circ\cot 88^\circ \cot 87^\circ...\tan 87^\circ \tan 88^\circ\tan 89^\circ$
$=(\cot 89^\circ\tan 89^\circ) (\cot 88^\circ\tan 88^\circ)\\ (\cot 87^\circ\tan 87^\circ)...(\cot 44^\circ\tan44^\circ)(\tan 45^\circ)$
$=1\times1\times1...\times1 \ \ (\because\cot\theta\tan\theta=1\text{and}\tan45^\circ=1)$
$\therefore\tan1^\circ\tan2^\circ\tan3^\circ...\tan89^\circ=1$

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