Question
The value of the expression
$3(1!) - 4(2!) + 5(3!) - 6(4!) ...... - 2008(2006)!+ (2007)!$ is  

Answer

c
$T_1 = (2 + 1)(1!) = 2! + 1!$
$T_2 = -(3 + 1)(2!) = (3! + 2!)$
$T_3 = (4 + 1)(3!) = 4! + 3!$
:
Sum $= 1$

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