MCQ
The value of the root $ \sqrt{\frac{16}{36}+\frac{1}{4}}$ is:
- A$ \frac{2}{5}$
- B$ \frac{1}{3}$
- ✓$\frac{5}{6}$
- D$ \frac{7}{6}$
✓
Answer
Correct option: C.
$\frac{5}{6}$
$\therefore \sqrt{\frac{16}{36}+\frac{1}{4}}$
$\therefore\sqrt{\frac{16}{36}+\frac{1}{4}}$
$=\sqrt{\frac{16+9}{36}} = \sqrt{\frac{25}{36}} = \frac{5}{6}$
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