MCQ
The value of $x$ in the given figure is:


- A$30^\circ$
- B$45^\circ$
- ✓$35^\circ$
- D$25^\circ$


$\angle\text{CDB}=\frac{110^\circ}{2}=55^\circ$
Now, $\angle\text{ADB}=90^\circ$ (Angle in a semicircle)
So, $\angle\text{ADC}=\text{x}=90^\circ-55^\circ=35^\circ$
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