MCQ
The value of $x = \sqrt {2 + \sqrt {2 + \sqrt {2 + .....} } } $is
- A$-1$
- B$1$
- ✓$2$
- D$3$
$⇒$ $(x - 2)(x + 1) = 0$ $⇒$ $x = 2, - 1$
But $\sqrt {2 + \sqrt {2 + .....} } \ne - 1$, so it is equal to $2.$
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$S_1$ : If $f(x)$ is a differentiable function with $f'(x)$ = $0$ in $(a, b)$ and $f(x)$ is increasing in $(a, b)$ , then $\frac {f(x)}{f\ '(x)}$ is also increasing in $(a, b).$
$ S_2$ : Both $sin\ x$ and $tan\ x$ are increasing function in $(0,\frac{\pi}{2})$. Which of the following is true