Question
The value of $x = \sqrt {2 + \sqrt {2 + \sqrt {2 + .....} } } $is

Answer

c
(c) $x = \sqrt {2 + x} $$⇒$  ${x^2} - x - 2 = 0$

$⇒$  $(x - 2)(x + 1) = 0$ $⇒$  $x = 2, - 1$

But $\sqrt {2 + \sqrt {2 + .....} } \ne - 1$, so it is equal to $2.$

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