The values of x for which the angle between a =2x^2 i +4x j + k , b =7 i -2 j +x k is obtuse and the angle between b and the z-axis is acute and less than 6 are:

The values of x for which the angle between a =2x^2 i +4x j + k ,…

MCQ

The values of x for which the angle between $\vec{\text{a}}=2\text{x}^2\hat{\text{i}}+4\text{x}\hat{\text{j}}+\hat{\text{k}},\vec{\text{b}}=7\hat{\text{i}}-2\hat{\text{j}}+\text{x}\hat{\text{k}}$is obtuse and the angle between $\vec{\text{b}}$ and the z-axis is acute and less than $\frac{\pi}{6}$ are:

A
$\text{x}>\frac{1}{2}$ or $\text{x}<0$
✓
$0<\text{x}<\frac{1}{2}$
C
$\frac{1}{2}<\text{x}<15$
D
$\phi$

✓

Answer

Correct option: B.

$0<\text{x}<\frac{1}{2}$

$\vec{\text{a}}=2\text{x}^2\hat{\text{i}}+4\text{x}\hat{\text{j}}+\hat{\text{k}}, \vec{\text{b}}=7\hat{\text{i}}-2\hat{\text{j}}+\text{x}\hat{\text{k}}$

Let the angle between vector a and vector b be A.

$\therefore\cos\text{A}=\frac{\vec{\text{a}}.\vec{\text{b}}}{|\vec{\text{a}}|\big|\vec{\text{b}}\big|}=\frac{\big(2\text{x}^2\hat{\text{i}}+4\text{x}\hat{\text{j}}+\hat{\text{k}}\big).\big(7\hat{\text{i}}-2\hat{\text{j}}+\text{x}\hat{\text{k}}\big)}{\big|2\text{x}^2\hat{\text{i}}+4\text{x}\hat{\text{j}}+\hat{\text{k}}\big|\big|7\hat{\text{i}}-2\hat{\text{j}}+\text{x}\hat{\text{k}}\big|}$

$=\frac{14\text{x}^2-8\text{x}+\text{x}}{\sqrt{4\text{x}^4+16\text{x}^2+1}\sqrt{49+4+\text{x}^2}}$

$=\frac{14\text{x}^2-8\text{x}+\text{x}}{\sqrt{4\text{x}^4+16\text{x}^2+1}\sqrt{53+\text{x}^2}}$

Now, $\angle\text{A}$ is an obtuse angle.

$\therefore\cos\text{A}<0$

$\Rightarrow\frac{14\text{x}^2-7\text{x}}{\sqrt{4\text{x}^4+16\text{x}^2+1}\sqrt{53+\text{x}^2}}<0$

$\Rightarrow14\text{x}^2-7\text{x}<0$

$\Rightarrow2\text{x}^2-\text{x}<0$

$\Rightarrow\text{x}(2\text{x}-1)<0$

$\Rightarrow\text{x}<0\ \&\ 2\text{x}-1>0$ or $\text{x}>0\ \&\ 2\text{x}-1<0$

$\Rightarrow\text{x}<0\ \&\ \text{x}>\frac{1}{2}$ or $\text{x}>0\ \&\ \text{x}<\frac{1}{2}$

$\Rightarrow\text{x}>0\ \&\ \text{x}<\frac{1}{2}$ (As there cannot be any number less than zero and greater than $\frac{1}{2}$)

$\Rightarrow\text{x}\in(0,\frac{1}{2})\dots(1)$

Let the equation of the z-axis be $\text{z}\hat{\text{k}}.$

And let the angle between $\vec{\text{b}}$ and z-axis be B.

$\therefore\cos\text{B}=\frac{\big(7\hat{\text{i}}-2\hat{\text{j}}+\text{x}\hat{\text{k}}\big).\big(\text{z}\hat{\text{k}}\big)}{\big|7\hat{\text{i}}-2\hat{\text{j}}+\text{x}\hat{\text{k}}\big|\big|\text{z}\hat{\text{k}}\big|}$

$=\frac{\text{xz}}{\text{z}\sqrt{49+4+\text{x}^2}}$

$=\frac{\text{x}}{\sqrt{53+\text{x}^2}}$

Now, angle B is acute and less than $\frac{\pi}{6}.$

$\therefore0<\frac{\text{x}}{\sqrt{53+\text{x}^2}}<\cos\frac{\pi}{6}$

$\Rightarrow0<\text{x}<\frac{\sqrt{3}}{2}\sqrt{53+\text{x}^2}\dots(2)$

From (1) and (2) we get

$0<\text{x}<\frac{1}{2}$

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