The values of x satisfying log3 (x2 + 4x + 12) = 2 are: - Vidyadip

MCQ

The values of x satisfying log₃ (x²+ 4x + 12) = 2 are:

A
2, −4
B
1, −3
C
−1, 3
D
−1, −3

✓

Answer

−1, −3

Solution:

The given equation is log₃(x² + 4x + 12) = 2

⇒ x² + 4x + 12 = 3²= 9

⇒ x² + 4x + 3 = 0

⇒ (x + 1) (x + 3) = 0

⇒ x = -1, -3

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