- ASlight less than half that of $N{H_4}Cl$
- ✓Half that of $N{H_4}Cl$
- CDouble that of $N{H_4}Cl$
- DDetermined by the amount of solid $N{H_4}Cl$ in the experiment
$N{H_4}Cl$ $\rightleftharpoons$ $N{H_3} + HCl$
$\therefore \alpha = 1$ $\therefore$ Experimental Molecular wt $=$ $\frac{{{\rm{nor}}{\rm{.mol}}{\rm{.wt}}{\rm{.}}}}{2}$
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$2 \mathrm{Fe}_{(\mathrm{s})}+\frac{3}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})}, \Delta \mathrm{H}^{\mathrm{o}}=-822 \mathrm{~kJ} / \mathrm{mol}$
$\mathrm{C}_{(\mathrm{s})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{(\mathrm{g})}, \Delta \mathrm{H}^{\mathrm{o}}=-110 \mathrm{~kJ} / \mathrm{mol}$
Then enthalpy change for following reaction
$3\mathrm{C}_{(\mathrm{s})}+\mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})} \rightarrow 2 \mathrm{Fe}_{(\mathrm{s})}+3 \mathrm{CO}_{(\mathrm{g})}$