MCQ
The vapour density of completely dissociated $N{H_4}Cl$ would be
  • A
    Slight less than half that of $N{H_4}Cl$
  • Half that of $N{H_4}Cl$
  • C
    Double that of $N{H_4}Cl$
  • D
    Determined by the amount of solid $N{H_4}Cl$ in the experiment

Answer

Correct option: B.
Half that of $N{H_4}Cl$
(b) $\frac{{{\rm{Normal}}\,\,{\rm{molecular}}\,\,{\rm{weight}}}}{{{\rm{experimental}}\,\,{\rm{molecular}}\,\,{\rm{wt}}{\rm{.}}}}$ $= 1 +$ $\alpha$

$N{H_4}Cl$ $\rightleftharpoons$ $N{H_3} + HCl$

$\therefore \alpha = 1$  $\therefore$ Experimental Molecular wt $=$ $\frac{{{\rm{nor}}{\rm{.mol}}{\rm{.wt}}{\rm{.}}}}{2}$

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