The variance of the data 2, 4, 6, 8, 10 is - Vidyadip

MCQ

The variance of the data $2, 4, 6, 8, 10$ is

A
$6$
B
$7$
✓
$8$
D
None of these

✓

Answer

Correct option: C.

$8$

c
(c) Here, $\bar x = \frac{{2 + 4 + 6 + 8 + 10}}{5} = 6$

Hence, variance = $\frac{1}{n}\Sigma {({x_i} - \overline x )^2}$

$ = \frac{1}{5}\{ {(2 - 6)^2} + {(4 - 6)^2} + {(6 - 6)^2} + {(8 - 6)^2} + {(10 - 6)^2}\} $

$ = \frac{1}{5}\left\{ {(16 + 4 + 0 + 4 + 16} \right\}$$ = \frac{1}{5}\left\{ {40} \right\}$ $ = 8$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 11 - 13. statistics→STD 11 - 13. statistics — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

Mr. $A$ has six children and atleast one child is a girl, then probability that Mr. $A$ has $3$ boys and $3$ girls, is -

Let $0 < \theta < \frac{\pi }{2}$. If the eccentricity of the hyperbola $\frac{{{x^2}}}{{{{\cos }^2}\,\theta }} - \frac{{{y^2}}}{{{{\sin }^2}\,\theta }} = 1$ is greater than $2$, then the length of its latus rectum lies in the interval

The number of elements in the set $S =\left\{\theta \in[0,2 \pi]: 3 \cos ^4 \theta-5 \cos ^2 \theta-2 \sin ^2 \theta+2=0\right\}$ is $...........$.

If the standard deviation of a variable $X$ is $\sigma,$ then the standard deviation of variable $\frac{\text{aX+b}}{\text{c}}$ is:

If $x{\sin ^3}\alpha + y{\cos ^3}\alpha = \sin \alpha \cos \alpha $ and $x\sin \alpha - y\cos \alpha = 0,$ then ${x^2} + {y^2} = $

The sum of all those terms which are rational numbers in the expansion of $\left(2^{1 / 3}+3^{1 / 4}\right)^{12}$ is:

Radius of circle touching $y-$axis at point $P(0,2)$ and circle $x^2 + y^2 = 16$ internally-

Let $A\, (2, 3)$ and $B\, (-4, 5)$ are two fixed points. $A$ point $P$ moves in such a way that $\Delta PAB = 12 \,sq. units$, then its locus is :-

Let $n$ be a fixed positive integer. Let a relation $R$ defined on $I ($the set of all integers$)$ as follows: $aRb$ iff $ \frac{\text{n}}{(\text{a}-\text{b}})$, that is, iff $a − b$ is divisible by $n$, then, the relation $R$ is:

The sum of the series 1 + 2 + 3 + 4 + 5 +………..n is: