MCQ
The velocity$-$time plot for a particle moving on a straight line is shown in the figure:
  • A
    The particle has a constant acceleration.
  • B
    The average speed in the interval $0$ to $10s$ is the same as the average speed in the interval $10s$ to $20s.$
  • C
    The particle has zero displacement.
  • Both $B$ and $C$

Answer

Correct option: D.
Both $B$ and $C$
  1. The slope of the $v-t$ graph gives the acceleration. For the given graph, the slope is constant. So, acceleration is constant.
  2. From $0$ to $10$ seconds, velocity is in positive direction and then in negative direction. This means that the particle turns around at $t = 10s.$
  3. Area in the $v-t$ curve gives the distance travelled by the particle.
Distance travelled in positive Direction $\neq$ Distance travelled in negative direction
$\therefore\text{Displacement}\neq\text{Zero}$
  1. The area of the $v-t$ graph from $t = 0s$ to $t = 10s$ is the same as that from $t = 10s$ to $t = 20s.$ So, the distance covered is the same. Hence, the average speed is the same.

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