Gujarat BoardEnglish MediumSTD 11 ScienceMATHSParabola1 Mark
MCQ
The vertex of the parabola $(y + a)^2 = 8a (x - a)$ is
A
(-a, -a)
✓
(a, -a)
C
(-a, a)
D
None of these
✓
Answer
Correct option: B.
(a, -a)
(a, a)
Solution:
Given:
The equation of the parabola is $(y + a)^2 = 8a (x - a)$.
Putting $X = x - a, Y = y + a$
$Y^2 = 8aX$
Vertex = $(X = 0, Y = 0) = (x - a = 0, y + a = 0) = (x = a, y = -a)$
Hence, the vertex is at (a, a).
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