MCQ
The volume of a cube a cube whose surface area is $96\ cm^2,$ is:
- A$16\sqrt{2}\text{cm}^3$
- B$32\ cm^3$
- ✓$64\ cm^3$
- D$216\ cm^3$
✓
Answer
Correct option: C.
$64\ cm^3$
Let,
$a \rightarrow$ Side of the cube
$V \rightarrow$ Volume of the cube
$A \rightarrow$ Surface area of the cube
We have,
$A = 96\ cm^2$
$6a^2 = 96 ($Since, $A = 6a^2)$
$a = 4\ cm$
So,
$V = a^3$
$= 4^3$
$= 64\ cm^3$
Thus, volume of the cube is $64\ cm^3.$
$a \rightarrow$ Side of the cube
$V \rightarrow$ Volume of the cube
$A \rightarrow$ Surface area of the cube
We have,
$A = 96\ cm^2$
$6a^2 = 96 ($Since, $A = 6a^2)$
$a = 4\ cm$
So,
$V = a^3$
$= 4^3$
$= 64\ cm^3$
Thus, volume of the cube is $64\ cm^3.$
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