Question
The volume of a cube is $512 \mathrm{~cm}^3$. Find its surface area.

Answer

Suppose that the side of the given cube is $x \mathrm{~cm}$.Volume of the cube $=512 \mathrm{~cm}^3$
Then $512=x^3$
$\Rightarrow x=\sqrt[3]{512}=8$
i.e., the side of the cube is $8 \ cm .$
$\therefore$ Surface area of the cube $=6 \mathrm{x}^2 \mathrm{~cm}^2=6 \times 8^2 \mathrm{~cm}^2=384 \mathrm{~cm}^2$

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