Question
The volume of a cube is $729\ cm^3$​​​​​​​. Find its surface area.

Answer

Let the edge of the cube be a.
As,
Volume of the cube $= 729\ cm^3$​​​​​​​
$\Rightarrow\text{a}^3=729$
$\Rightarrow\text{a}=\sqrt[3]{729}$
$\Rightarrow486\text{cm} ^2$
Now,
Surface area of the cube $= 6a^2$
$= 6 \times 9 \times 9$
$= 486\ cm^2$​​​​​​​
So, the surface area of the cube is $486\ cm2$.

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