Question
The width of the $nth$ $HPZ$  will be

Answer

(b)Width of $nth$ $HPZ$  ${B_n} = {r_n} - {r_{n - 1}}$
${r_n} = \sqrt {nb\lambda } $, ${r_{n - 1}} = \sqrt {(n - 1)b\lambda } $
${B_n} = \sqrt {nb\lambda } - \sqrt {(n - 1)b\lambda } = \sqrt {b\lambda } \,[\sqrt n - \sqrt {(n - 1)} ]$

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