By definition the work function is the minimum energy $($in electron volts$)$ needed to remove an electron from a solid to a point immediately outside the solid surface $($or energy needed to move an electron from the Fermi level into vacuum$).$
Hence, if the work function of cesium metal is $2ev$, it means that the energy necessary to emit electrons from metal surface is $2eV.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List $I$ | List $II$ |
| $(A)$ Microwave | $(I)$ $400\,nm$ to $1\,nm$ |
| $(B)$ Ultraviolet | $(II)$ $1\,nm$ to $10^{-3}\,nm$ |
| $(C)$ $X-$Ray | $(III)$ $1\,mn$ to $700\,nm$ |
| $(D)$ Infra-red | $(IV)$ $0.1\,m$ to $1\,mm$ |
Choose the correct answer from the options given below:
