MCQ
The Wurtz-Fittig reaction involves condensation of
- Atwo molecules of aryl halides
- ✓one molecule of each of aryl- halide and alkyl-halide.
- Cone molecule of each of aryl-halide and phenol.
- Dtwo molecules of aralkyl-halides.
${C_6}H_5Cl + 2Na + ClC{H_3} \to \mathop {{C_6}{H_5}C{H_3}}\limits_{{\text{Toluene}}} + 2NaCl$
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$Cr _{2} O _{7}^{2-}+14 H ^{+}+6 e ^{-} \rightarrow 2 Cr ^{3+}+7 H _{2} O$
The amount of $Cr ^{3+}$ obtained was $0.104\, g$. The
efficiency of the process(in\%) is
(Take : $F =96000\, C$, At. mass of chromium $=52$ )

$(i)$ $PtCl _{4} . 5 NH _{3}$ $(ii)$ $PtCl _{4} . 4 NH _{3}$ $(iii)$ $PtCl _{4} . 3 NH _{3}$ $(iv)$ $PtCl _{4}. 2 NH _{3}$
Follow the order
Reason : The presence of additional $d-$ electron offer poor screening effect for the outer electrons from increased nuclear charge.