Question
Then find the value of:
✓
Answer
Given,
$=2 \times(2\times6+3)+\Big(\frac{3}{2}\times3 +7\Big)-(1-3)$
$=2\times(12+3)+\Big(\frac{9}{2}+7\Big)-(-2)$
$2\times 15 +\Big(\frac{23}{2}\Big)+2=30+2+\frac{23}{2}$
$=23+\frac{23}{2}=\frac{32\times2+23}{2}=\frac{64+23}{3}$
$=\frac{87}{2}$
$=2 \times(2\times6+3)+\Big(\frac{3}{2}\times3 +7\Big)-(1-3)$
$=2\times(12+3)+\Big(\frac{9}{2}+7\Big)-(-2)$
$2\times 15 +\Big(\frac{23}{2}\Big)+2=30+2+\frac{23}{2}$
$=23+\frac{23}{2}=\frac{32\times2+23}{2}=\frac{64+23}{3}$
$=\frac{87}{2}$
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