Question
Then find the value of:
Then find the value of:✓
Answer
Given, 
$=\frac{1}{2}\Big(\frac{3}{2}\times2+7\Big)+(8-3) -3(2\times0+3)$ $=\frac{1}{2}(10)+5-3(3)$ $= 5 + 5 -9 =1$
$=\frac{1}{2}\Big(\frac{3}{2}\times2+7\Big)+(8-3) -3(2\times0+3)$ $=\frac{1}{2}(10)+5-3(3)$ $= 5 + 5 -9 =1$
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