Question
There are $200$ natural numbers between $100^2$ and $101^2$.

Answer

natural numbers between $100^2$ and $101^2$
$= 101^2- 100^2- 1[\because$ Natural numbers between $a$ and $b = b - a - 1]$
$= (101 + 100)(101 - 100) - 1 = 200$

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