MCQ
There are two equipotential surface as shown in figure. The distance between them is r. The charge of –q coulomb is taken from the surface A to B, the resultant work done will be
  • A
    $W=\frac{1}{4 \pi \varepsilon_0} \frac{q}{r}$
  • B
    $W=\frac{1}{4 \pi \varepsilon_0} \frac{q}{r^2}$
  • C
    $W=-\frac{1}{4 \pi \varepsilon_0} \frac{q}{r^2}$
  • $W = Zero$

Answer

Correct option: D.
$W = Zero$
(d) $W = Zero$

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