There is an air filled $1\,pF$ parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to $2\,pF$. The dielectric constant of wax is
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A circuit shown in the figure consists of a battery of $emf$ $10$ $V$ and two capacitance $C_1$ and $C_2 $ of capacitances $1.0$ $ \mu F$ and $2.0$ $\mu F$ respectively. The potential difference $V_A - V_B$ is $5\,V$
The electric potential in volts due to an electric dipole of dipole moment $2 \times 10^{-8}$ coulomb-metre at a distance of $3 \,m$ on a line making an angle of $60^{\circ}$ with the axis of the dipole is ..........
Five conducting parallel plates having area $A$ and separation between them $d$, are placed as shown in the figure. Plate number $2$ and $4$ are connected wire and between point $A$ and $B$, a cell of emf $E$ is connected. The charge flown through the cell is
A parallel plate capacitor with air between plates has a capacitance of $8\,\mu F$ what will be capacitance if distance between plates is reduced by half, and the space between them is filled with a substance of dielectric constant $6$ ?.....$\mu F$
A sphere carrying charge of $Q$ having weight $w$ falls under gravity between a pair of vertical plates at a distance of $d$ from each other. When a potential difference $V$ is applied between the plates the acceleration of sphere changes as shown in the figure, to along line $BC$. The value of $Q$ is :-
An electric dipole is placed as shown in the figure.The electric potential (in $10^2\,V$ ) at point $P$ due to the dipole is $\left(\in_0=\right.$ permittivity of free space and $\left.\frac{1}{4 \pi \in_0}=K\right)$ :