There is an electric field $E$ in $X$-direction. If the work done on moving a charge $0.2\,C$ through a distance of $2\,m$ along a line making an angle $60^\circ $ with the $X$-axis is $4.0\;J$, what is the value of $E$........ $N/C$
AIPMT 1995, Medium
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(d) $W = qV = qE × d$
$4 = 0.2× E × (2 cos $$60^\circ $)
$= 0.2 E × (2 × 0.5)$
$E = \frac{4}{{0.2}} = 20\,N{C^{ - 1}}$
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$\varepsilon(x)=\varepsilon_{0}+k x, \text { for }\left(0\,<\,x \leq \frac{d}{2}\right)$
$\varepsilon(x)=\varepsilon_{0}+k(d-x)$, for $\left(\frac{d}{2} \leq x \leq d\right)$