Question
Three boys step off together from the same place. If their steps measure $36\ cm, 48\ cm$ and $54\ cm$, at what distance from the starting point will they again step together?

Answer

From the starting point, they will step together again when they travel a distance that is exactly divisible by the lengths of their steps. The least distance from the starting point where they will step together will be given by the $LCM$ of $36, 48$ and $54.$
$\begin{array}{c|c}2&36,48,54\\\hline2&18,24,27\\\hline3&9,12,27\\\hline3&3,4,9\\\hline3&1,4,3\\\hline2&1,4,1\\\hline2&1,2,1\\\hline&1,1,1\end{array}$
The required distance $= 2 \times 2 \times 3 \times 3 \times 3 \times 2 \times 2 = 16 \times 27 = 432\ cm$
They will step together again at a distance of $432\ cm$ from the starting point

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