Question
Three coins are tossed once. Find the probability of getting: 2 heads

Answer

When three coins are tossed then total outcomes, S = {HHH, HHT, HTH, THH, TTH, HTT, TTT, THT}
Where s is sample space and here n(S) = 8
Let A be the event of getting 2 heads
n(A) = 3
P(getting 2 heads) = P(A) = $\frac{\mathrm{n}(\mathrm{A})}{\mathrm{n}(\mathrm{S})}=\frac{3}{\mathrm{8}}$

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