Question
Three coins are tossed once. Find the probability of getting: almost two tails
✓
Answer
When three coins are tossed then the sample space S = {HHH, HHT, HTH, THH, TTH, HTT, TTT, THT}
Where s is sample space and here n(S) = 8
Let A be the event of getting at most 2 tails
n(A) = 7
P(getting almost 2 tails) = P(A) = $\frac{\mathrm{n}(\mathrm{A})}{\mathrm{n}(\mathrm{S})}=\frac{7}{\mathrm{8}}$
Where s is sample space and here n(S) = 8
Let A be the event of getting at most 2 tails
n(A) = 7
P(getting almost 2 tails) = P(A) = $\frac{\mathrm{n}(\mathrm{A})}{\mathrm{n}(\mathrm{S})}=\frac{7}{\mathrm{8}}$
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