MCQ
Three dice are rolled. If the probability of getting different numbers on the three dice is $\frac{p}{q}$, where $p$ and $q$ are co-prime, then $q- p$ is equal to
- ✓$4$
- B$3$
- C$1$
- D$2$
Favourable outcomes ${ }^6 p _3=120$
$\Rightarrow \text { Probability }=\frac{120}{216}=\frac{5}{9}$
$\Rightarrow p =5, q =9$
$\Rightarrow q - p =4$
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